What is the antiderivative of x/(7x^2+3)^5?
1 Answer
May 29, 2016
Explanation:
We wish to find:
intx/(7x^2+3)^5dx
This is a prime case for substitution. Let
Note that we already have
=1/14int(14x)/(7x^2+3)^5dx
Now substitute in
=1/14int(du)/u^5=1/14intu^-5du
Integrating
=1/14(u^-4/(-4))+C=-1/(56u^4)+C=-1/(56(7x^2+3)^4)+C