What is the antiderivative of #1/ x^2#?

1 Answer
Eric Sandin
Jun 6, 2015

It's as easy as taking the negative exponent and integrate with the exponent rule.

The antiderivative is the same as the integral, and I guess you want to compute #int1/x^2dx#. Since #1/x^2=x^(-2)#, let's calculate the integral using the exponent algorythm:

#intx^(-2)dx=x^(-1)/(-1)+C=-1/x+C#

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