What is the antiderivative of #1/(1+x^2)#?

1 Answer
VNVDVI
Mar 24, 2018

#tan^-1(x)+C#

Explanation:

We want a function which, when differentiated, will yield #1/(1+x^2).#

#tan^-1(x)# fulfills this requirement, as #d/dxtan^-1(x)=1/(1+x^2).#

We also add in an arbitrary constant #C,# any constant could be part of our antiderivative, as differentiating a constant yields zero.

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