What is Kp? What goes on in a Kp equation?
1 Answer
Conventionally, it is reported in implied units of
It is used in a mass action expression to determine equilibrium partial pressures. Here is a nice example...
1"NH"_4"Cl"(s) rightleftharpoons color(red)(1)"NH"_3(g) + color(red)(1)"HCl"(g)
"I"" "-" "" "" "" "" "0" "" "" "0
"C"" "-" "" "" "" "+P_i" "+P_i
"E"" "-" "" "" "" "color(white)(//.)P_i" "" "P_i
In this case, we see a solid goes into the expression as
I have purposefully highlighted the coefficients, as they become the exponent for gaseous reactants.
The mass action expression is therefore:
K_P = ((P_(NH_3))^color(red)(1)(P_(HCl))^color(red)(1))/1
But since the coefficients for both products are the same,
As a result, if the
6.25 = P_(NH_3)P_(HCl) = P_i^2
So, the partial pressures at equilibrium are each:
=> P_i = P_(NH_3) = P_(HCl) = sqrt(6.25) = ul"2.5 atm"
CHALLENGE: What is the total pressure at equilibrium? HINT: What is Dalton's law?