Considering the reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) If a solution is made containing initial [SO2Cl2]= 0.021M, at equilibrium, [Cl2]= 1.3×10−2M. What are the equilibrium concentrations of SO2Cl2 and SO2?
1 Answer
Sep 14, 2014
At equilibrium, [ SO₂Cl₂] = 0.087 mol/L and [SO₂] = 1.3 × 10⁻² mol/L.
First, write the balanced chemical equation with an ICE table.
SO₂Cl₂(g) ⇌ SO₂(g) + Cl₂(g)
I/mol·L⁻¹: 0.021; 0; 0
C/mol·L⁻¹: -
E/mol·L⁻¹: 0.021 -
At equilibrium,
So
Then
and