What is $K_{e q}$ $K_(eq)$ for the reaction $2 S O_{3} (g)$ $2SO_3(g)$ ⇌ $2 S O_{2} (g)$ $2SO_2(g)$ + $O_{2} (g)$ $O_2 (g)$ ?

Question

2047 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-10T09:12:59

Unknown at this stage. But we can certainly write the equilibrium expression.

$2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$ $2SO_3(g)rightleftharpoons2SO_2(g) + O_2(g)$

$K_{c}$ $K_c$ $=$ $=$ $\frac{{[S O_{2} (g)]}_{2}^{2} [O_{2} (g)]}{{[S O_{3} (g)]}_{3}^{2}}$ $([SO_2(g)]^2[O_2(g)])/([SO_3(g)]^2)$

This can be turned into an expression relating the partial pressures of each component at equilibrium.

What is KeqK_(eq) for the reaction 2SO3(g)2SO_3(g) ⇌ 2SO2(g)2SO_2(g) + O2(g) O_2 (g)?