Two circles have the following equations: (x +3 )^2+(y -1 )^2= 64 and (x -7 )^2+(y +2 )^2= 25 . Does one circle contain the other? If not, what is the greatest possible distance between a point on one circle and another point on the other?

1 Answer
Nov 16, 2017

One circle does not contain other. Circles intersect each other. Greatest possible distance between point on one circle and another point on the other is 23.44

Explanation:

By general:
(x-x_0)^2+(y-y_0)^2=R^2

=> center: (-x_0,-y_0)
=> R: sqrt(R^2)

First let's find the centers and the R of each circle:

For (x+3)^2+(y-1)^2=64
Center: (-3,1)
R_1: sqrt64=8

For (x-7)^2+(y+2)^2=25
Center: (7,-2)
R_2: sqrt25=5

The distance between two points given by Protagoras:
d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)
=>
The distance between the centers of the circles above given by Protagoras:
d=sqrt((7-(-3))^2+((-2)-1)^2)=sqrt109~~10.44

R_1+R_2=8+5=13 and R_1-R_2=8-5=3

We saw that R_1+R_2>d and R_1-R_2 < d therefore circles intersect each other. Greatest possible distance between point on one circle and another point on the other is 8+5+10.44=23.44

[For details see here.](https://socratic.org/questions/two-circles-have-the-following-equations-x-4-2-y-3-2-9-and-x-4-2-y-1-2-16-does-o#306687)

graph{((x+3)^2+(y-1)^2-64)((x-7)^2+(y+2)^2-25)=0 [-20, 20, -10, 10]}