The area of a particular triangle can be represented by $x^2+3/2x-9/2$ . What are its base and height in terms of x?

Question

1987 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-06T08:21:27

The answer is $(2x-3)$ and $(x+3)$

The area of a triangle is $=1/2*b*h$

so,

$1/2*b*h=x^2+3/2x-9/2$

$b*h=2x^2+3x-9$

$=(2x-3)(x+3)$

Therefore,

$b=(2x-3)$

$h=(x+3)$

or inversely

The area of a particular triangle can be represented by x^2+3/2x-9/2x^2+3/2x-9/2. What are its base and height in terms of x?