How do you simplify $-3a^2b(9a^2-4b^2)$ ?

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How do you simplify $-3a^2b(9a^2-4b^2)$ ?

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Answer 1 · 2014-10-30T01:00:54

In order to simplify $-3a^2b(9a^2-4b^2)$ you would use the distributive property and multiply $-3a^2b$ by each of the terms in the parenthesis.
$-3a^2b(9a^2)$ - $-3a^2b(4b^2)$

$(a^2)(a^2)$ = (a)(a)(a)(a) = $a^4$ $(b)(b^2)$ = (b)(b)(b) = $b^3$

$-27a^4b - (-12a^2b^3)$

Simplify the signs.

$-27a^4b + 12a^2b^3$

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How do you simplify $-3a^2b(9a^2-4b^2)$ ?

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How do you simplify -3a^2b(9a^2-4b^2)-3a^2b(9a^2-4b^2)?

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How do you simplify $-3a^2b(9a^2-4b^2)$ ?