How do you multiply and simplify $6 a b (- 10 a^{2} b^{3} + c^{5})$ $6ab(-10a^2 b^3+c^5)$ ?

Question

4175 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-18T10:09:54

$\Rightarrow - 60 a^{3} b^{4} + 6 a b c^{5}$ $color(green)(=> -60a^3 b^4 + 6abc^5$

$6 a b \cdot (- 10 a^{2} b^{3} + c^{5})$ $6ab * (-10a^2b^3 + c^5)$

$\Rightarrow 6 a b \cdot (- 10 a^{2} b^{3} + 6 a b \cdot c^{5}$ $=> 6ab * (-10a^2b^3 + 6ab * c^5$

$\Rightarrow - 60 a^{3} b^{4} + 6 a b c^{5}$ $color(green)(=> -60a^3 b^4 + 6abc^5$

How do you multiply and simplify 6ab(−10a2b3+c5)6ab(-10a^2 b^3+c^5)?