How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#?

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How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#?

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Answer 1 · 2015-04-03T16:54:35

10#n^7# -30 #n^12#

5#n^2# will multiply with both the terms inside the parentheses. On multiplication the exponents would add with the same base n. Final result would be 10#n^7# -30#n^12# .

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How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#?

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