How do you multiply $(5n^2)(2n^5 - 2n^3 3n^7)$ ?

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How do you multiply $(5n^2)(2n^5 - 2n^3 3n^7)$ ?

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Answer 1 · 2015-04-03T16:54:35

10 $n^7$ -30 $n^12$

5 $n^2$ will multiply with both the terms inside the parentheses. On multiplication the exponents would add with the same base n. Final result would be 10 $n^7$ -30 $n^12$ .

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How do you multiply $(5n^2)(2n^5 - 2n^3 3n^7)$ ?

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How do you multiply (5n^2)(2n^5 - 2n^3 3n^7)(5n^2)(2n^5 - 2n^3 3n^7)?

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How do you multiply $(5n^2)(2n^5 - 2n^3 3n^7)$ ?