Multiply the polynomial by the monomial?

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Multiply the polynomial by the monomial?

5b( $b^{5}$ $b^5$ - $\frac{1}{10}$ $1/10$ $b^{3}$ $b^3$ + $\frac{1}{15}$ $1/15$ $b^{2}$ $b^2$ - $\frac{1}{25}$ $1/25$ b+1)

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Answer 1 · 2016-07-25T17:33:10

$= 5 b^{6} - \frac{1}{2} b^{4} + \frac{1}{3} b^{3} - \frac{1}{5} b^{2} + 5 b$ $=5b^6-1/2b^4+1/3b^3-1/5b^2+5b$

Explanation:

Multiplication distributes term by term, thus:
$5 b (b^{5} - \frac{1}{10} b^{3} + \frac{1}{15} b^{2} - \frac{1}{25} b + 1)$ $5b(b^5-1/10b^3+1/15b^2-1/25b+1)$
$= 5 b \times b^{5} - 5 b \times \frac{1}{10} b^{3} + 5 b \times \frac{1}{15} b^{2} - 5 b \times \frac{1}{25} b + 5 b \times 1$ $=5b\timesb^5-5b\times1/10b^3+5b\times1/15b^2-5b\times1/25b+5b\times1$

Simplifying gets you:
$= 5 b^{6} - \frac{1}{2} b^{4} + \frac{1}{3} b^{3} - \frac{1}{5} b^{2} + 5 b$ $=5b^6-1/2b^4+1/3b^3-1/5b^2+5b$

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Multiply the polynomial by the monomial?

5b( $b^{5}$ $b^5$ - $\frac{1}{10}$ $1/10$ $b^{3}$ $b^3$ + $\frac{1}{15}$ $1/15$ $b^{2}$ $b^2$ - $\frac{1}{25}$ $1/25$ b+1)

1 Answer

Explanation:

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Multiply the polynomial by the monomial?

5b(b5b^5-1101/10b3b^3+1151/15b2b^2-1251/25b+1)

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Explanation:

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5b( $b^{5}$ $b^5$ - $\frac{1}{10}$ $1/10$ $b^{3}$ $b^3$ + $\frac{1}{15}$ $1/15$ $b^{2}$ $b^2$ - $\frac{1}{25}$ $1/25$ b+1)