Maria is painting the trim on the top of a building. She drops her paintbrush. The paintbrush has a velocity of 29.4 m/s when it hits the ground 3 s later. What is the acceleration of the paintbrush?

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Maria is painting the trim on the top of a building. She drops her paintbrush. The paintbrush has a velocity of 29.4 m/s when it hits the ground 3 s later. What is the acceleration of the paintbrush?

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Answer 1 · 2017-05-26T07:55:49

$a=9.8m/s^2$

Explanation:

Use the formula $a=(v_f-v_i)/(t_f-t_i)$ where $a$ is the acceleration, $v_f$ the final velocity, $v_i$ the initial velocity, $deltat$ the change in time, which can also be written as $t_f-t_i$ .

3 seconds later suggests that the change in time was 3 seconds.

The final velocity is 29.4m/s

The initial velocity is 0 because that was the velocity of the paintbrush just as it started its descent.

Therefore,
$a=(29.4-0)/3$
$a=9.8$

This is the speed of acceleration due to gravity on Earth. Initially, you could've solved it by looking at it but I wanted to give you how to work out answers like this.

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Maria is painting the trim on the top of a building. She drops her paintbrush. The paintbrush has a velocity of 29.4 m/s when it hits the ground 3 s later. What is the acceleration of the paintbrush?

1 Answer

Explanation:

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