If an object with uniform acceleration (or deceleration) has a speed of $5 m/s$ at $t=0$ and moves a total of 125 m by $t=8$ , what was the object's rate of acceleration?

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Answer 1 · 2016-01-28T05:03:11

The acceleration is $"1 m/s"^2"$ .

We will use the following equation to determine acceleration.

$color(red)(a=(v_f-v_i)/(Delta t))$ ,

where $a="acceleration"$ , $v_f="final velocity"$ , $v_i="initial velocity"$ , and $Delta t="time interval"$ .

However, we must first determine the final velocity using the following equation.

$color(blue)(v_f=(Deltad)/(Delta t))$ ,

where $Delta d="change in position"$ , and $Delta t="time interval"$ .

$v_f=(125"m")/(8"s")$

$v_f="15.625 m/s"$

Now that we have the final velocity, we can use the first equation to determine the acceleration.

$color(red)(a=(v_f-v_i)/(Delta t))$

$color(red)(a=((15.625"m/s")-(5"m/s"))/(8"s"))$

$color(red)(a=(10.625"m/s")/(8"s"))$

$color(red)(a="1 m/s"^2")$ (rounded to one significant figure)

If an object with uniform acceleration (or deceleration) has a speed of 5 m/s5 m/s at t=0t=0 and moves a total of 125 m by t=8t=8, what was the object's rate of acceleration?