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If an object with uniform acceleration (or deceleration) has a speed of $4 m/s$ at $t=0$ and moves a total of 8 m by $t=4$ , what was the object's rate of acceleration?

1 Answer

Dec 11, 2015

I found a deceleration of $-1.0m/s^2$

Explanation:

We can try to use:
$x_f-x_i=v_it+1/2at^2$
with:
$x_f-x_i=8m$
$t=4s$ (I think)
$v_i=4m/s$
to get:
$8=4*4+1/2a(4)^2$
$8=16+8a$
$a=-8/8=-1.0m/s^2$

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