If an object with uniform acceleration (or deceleration) has a speed of $4 \frac{m}{s}$ $4 m/s$ at $t = 0$ $t=0$ and moves a total of 18 m by $t = 5$ $t=5$ , what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of $4 \frac{m}{s}$ $4 m/s$ at $t = 0$ $t=0$ and moves a total of 18 m by $t = 5$ $t=5$ , what was the object's rate of acceleration?

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Answer 1 · 2016-04-30T10:21:37

$a = 0, 16 \frac{m}{s^{2}} acceleration$ $a=0,16 " "m/s^2" acceleration"$
$a = - 0, 16 \frac{m}{s^{2}} deceleration$ $a=-0,16" "m/s^2" deceleration"$
$\frac{acceleration}{deceleration} = - 1$ $("acceleration")/("deceleration")=-1$

Explanation:

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$in figure-1:$ $"in figure-1:"$
$area under graph is equal to displacement of object$ $"area under graph is equal to displacement of object"$

$18=((4+4+Delta v)*5)/2$

$36=40+5 Delta v" "5 Delta v=36-40" "5 Delta v=4 " " Delta v=4/5=0,8" "m/s$

$tan alpha=a=(Delta v)/(Delta t)$

$a=(0,8)/5$

$a=0,16 " "m/s^2" acceleration"$

$"in figure-2"$

$18=((4+4-Delta v)*5)/2$

$36=(8-Delta v)5$

$36=40-5 Delta v$

$5v=40-36$

$5v=4$
$v=4/5=0,8 " "m/s$

$tan beta=a=-(0,8)/5$

$a=-0,16" "m/s^2" deceleration"$

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If an object with uniform acceleration (or deceleration) has a speed of $4 \frac{m}{s}$ $4 m/s$ at $t = 0$ $t=0$ and moves a total of 18 m by $t = 5$ $t=5$ , what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of 4 m/s4ms4 m/s at t=0t=0t=0 and moves a total of 18 m by t=5t=5t=5, what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of $4 \frac{m}{s}$ $4 m/s$ at $t = 0$ $t=0$ and moves a total of 18 m by $t = 5$ $t=5$ , what was the object's rate of acceleration?