If an object with uniform acceleration (or deceleration) has a speed of $4 \frac{m}{s}$ $4 m/s$ at $t = 2$ $t=2$ and moves a total of 25 m by $t = 6$ $t=6$ , what was the object's rate of acceleration?

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Answer 1 · 2018-04-23T05:34:37

The acceleration is $= 1.125 m s^{- 2}$ $=1.125ms^-2$

The initial speed is $u = 4 m s^{- 1}$ $u=4ms^-1$

The distace is $s = 25 m$ $s=25m$

The time is $Deltat=6-2=4s$

Apply the equation of motion

$s=uDeltat+1/2a(Deltat)^2$

The acceleration is

$a=(s-uDeltat)/(1/2(Deltat)^2)$

$=(25-4xx4)/(1/2xx4^2)$

$=(9)/(8)$

$=1.125ms^-$

If an object with uniform acceleration (or deceleration) has a speed of 4 m/s4ms4 m/s at t=2t=2t=2 and moves a total of 25 m by t=6t=6t=6, what was the object's rate of acceleration?