If an object with uniform acceleration (or deceleration) has a speed of $3 \frac{m}{s}$ $3 m/s$ at $t = 0$ $t=0$ and moves a total of 80 m by $t = 4$ $t=4$ , what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of $3 \frac{m}{s}$ $3 m/s$ at $t = 0$ $t=0$ and moves a total of 80 m by $t = 4$ $t=4$ , what was the object's rate of acceleration?

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Answer 1 · 2017-10-01T18:42:19

Using the kinematic formula $D = v_{i} \cdot t + \frac{1}{2} a t^{2}$ $D =v_i*t+1/2at^2$ ,
$D = 80 m$ $D=80m$
$t = 4 s$ $t=4s$
$v_{i} = 3 \frac{m}{s}$ $v_i=3m/s$
$a = ?$ $a=?$

$80m = 3m/cancels*4cancels+ 1/2 color(blue)(a) *4^2s$
$80m-12m=8*color(blue)(a$
$72m=8*color(blue)(a$
$a=72/8=9m/s^2$

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If an object with uniform acceleration (or deceleration) has a speed of $3 \frac{m}{s}$ $3 m/s$ at $t = 0$ $t=0$ and moves a total of 80 m by $t = 4$ $t=4$ , what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of 3 m/s3ms3 m/s at t=0t=0t=0 and moves a total of 80 m by t=4t=4t=4, what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of $3 \frac{m}{s}$ $3 m/s$ at $t = 0$ $t=0$ and moves a total of 80 m by $t = 4$ $t=4$ , what was the object's rate of acceleration?