If an object with uniform acceleration (or deceleration) has a speed of $3 \frac{m}{s}$ $3 m/s$ at $t = 0$ $t=0$ and moves a total of 25 m by $t = 3$ $t=3$ , what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of $3 \frac{m}{s}$ $3 m/s$ at $t = 0$ $t=0$ and moves a total of 25 m by $t = 3$ $t=3$ , what was the object's rate of acceleration?

1 Answer

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Answer 1 · 2017-06-07T17:16:46

I got: $\pm 3.5 \frac{m}{s^{2}}$ $+-3.5m/s^2$

Explanation:

I think that you can have two options depending upon the final velocity giving either a positive or negative (deceleration) acceleration. Also I imagine the time in seconds.
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If an object with uniform acceleration (or deceleration) has a speed of $3 \frac{m}{s}$ $3 m/s$ at $t = 0$ $t=0$ and moves a total of 25 m by $t = 3$ $t=3$ , what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of 3ms3 m/s at t=0t=0 and moves a total of 25 m by t=3t=3, what was the object's rate of acceleration?

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If an object with uniform acceleration (or deceleration) has a speed of $3 \frac{m}{s}$ $3 m/s$ at $t = 0$ $t=0$ and moves a total of 25 m by $t = 3$ $t=3$ , what was the object's rate of acceleration?