If an object with uniform acceleration (or deceleration) has a speed of $2 \frac{m}{s}$ $2 m/s$ at $t = 0$ $t=0$ and moves a total of 12 m by $t = 5$ $t=5$ , what was the object's rate of acceleration?

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Answer 1 · 2015-12-12T13:10:05

$0.16 {m/s}^{2}$ $0.16"m/s"^2$

Use this equation of motion:

$s = u t + \frac{1}{2} a t^{2}$ $s=ut+1/2at^2$

The value of $t = 5$ $t=5$ is used as this is the total time for the journey:

$:.12=(2xx5)+(0.5xxaxx5^2)$

$:.a=2/(0.5xx25)=0.16"m/s"^2$

If an object with uniform acceleration (or deceleration) has a speed of 2 m/s2ms2 m/s at t=0t=0t=0 and moves a total of 12 m by t=5t=5t=5, what was the object's rate of acceleration?