If an object with uniform acceleration (or deceleration) has a speed of $12 m/s$ at $t=0$ and moves a total of 48 m by $t=6$ , what was the object's rate of acceleration?

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Answer 1 · 2018-03-05T18:26:58

For constant acclertion ( $a$ ) against the direction of motion or deceleration,we can apply,

$s=ut -1/2at^2$ where, $u$ is the initial velocity and $s$ is the displacement in $ts$

Given, $s=48m,t=6s,u=12ms^-1$

so, $a=1.34ms^-2$

If an object with uniform acceleration (or deceleration) has a speed of 12 m/s12 m/s at t=0t=0 and moves a total of 48 m by t=6t=6, what was the object's rate of acceleration?