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If an object with uniform acceleration (or deceleration) has a speed of $12 m/s$ at $t=0$ and moves a total of 22 m by $t=4$ , what was the object's rate of acceleration?

1 Answer

Dec 16, 2015

$-3.25"m/s"^2$

Explanation:

Use the equation of motion:

$s=ut+1/2at^2$

$:.22=(12xx4)+(0.5xxaxx4^2)$

$:.22=48+8a$

$:.a=-26/8=-3.25"m/s"^2$

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