If an object is moving at 60 m/s and accelerates to 145 m/s over 5 seconds, what was the object's rate of acceleration?

1 Answer
Meave60
Feb 24, 2016

The acceleration is "17 m/s"^2".

Explanation:

Use the formula a=(v_f-v_i)/(Delta t), where a is acceleration, v_i is initial velocity, v_f is final velocity, and Delta t is time interval.

Known
v_i="60 m/s"
v_f="145 m/s"
Delta t="5 s"

Unknown
a

Solution
Substitute the known variables into the formula and solve.

a=(v_f-v_i)/(Delta t)

a=(145"m/s"-60"m/s")/(5"s")

a=(85"m/s")/(5"s")

a="17 m/s"^2"

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