If an object is moving at $5 \frac{m}{s}$ $5 m/s$ and accelerates to $35 \frac{m}{s}$ $35 m/s$ over 10 seconds, what was the object's rate of acceleration?

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Answer 1 · 2016-01-25T01:43:23

Data:-

Initial Velocity $= v_{i} = 5 \frac{m}{s}$ $=v_i=5m/s$

Final Velocity $= v_{f} = 35 \frac{m}{s}$ $=v_f=35m/s$

Time Taken $= t = 10 s$ $=t=10s$

Acceleration $= a = ? ?$ $=a=??$

Sol:-

We know that:

$v_{f} = v_{i} + a t$ $v_f=v_i+at$

$\Rightarrow 35 = 5 + a \cdot 10$ $implies 35=5+a*10$

$\Rightarrow 30 = 10 a$ $implies 30=10a$

$\Rightarrow a = 3 \frac{m}{s^{2}}$ $implies a=3m/s^2$

Hence, the rate of acceleration is $3 \frac{m}{s^{2}}$ $3m/s^2$ .

If an object is moving at 5ms5 m/s and accelerates to 35ms35 m/s over 10 seconds, what was the object's rate of acceleration?