If an object is moving at $4 \frac{m}{s}$ $4 m/s$ and accelerates to $6 \frac{m}{s}$ $6 m/s$ over 3 seconds, what was the object's rate of acceleration?

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Answer 1 · 2016-04-12T06:11:53

$a = \frac{2}{3} \frac{m}{s^{2}}$ $a=2/3 m/s^2$

$v_{i} = 4 \frac{m}{s} initial velocity of object$ $v_i=4 m/s" initial velocity of object"$

$v_{l} = 6 \frac{m}{s} last velocity of object$ $v_l=6 m/s" last velocity of object"$

$t = 3 s$ $t=3 s$

$a = ? acceleration of object$ $a=?" acceleration of object"$

$"the object's rate of acceleration is given as "a=(Delta v)/(Delta t)$

$Delta v=v_l-v_i=6-4=2 m/s$

$Delta t=3-0=3$

$a=2/3 m/s^2$

If an object is moving at 4 m/s4ms4 m/s and accelerates to 6 m/s6ms6 m/s over 3 seconds, what was the object's rate of acceleration?