If an object is moving at $3 \frac{m}{s}$ $3 m/s$ and accelerates to $19 \frac{m}{s}$ $19 m/s$ over 2 seconds, what was the object's rate of acceleration?

Question

1880 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-09T15:02:16

it is $8 \frac{m}{s^{2}}$ $8m/s^2$ .

we can use the following formula for calculating the acceleration...

$a = \frac{v - u}{t}$ $a=(v-u)/t$

so...

$a = \frac{19 - 3}{2}$ $a=(19-3)/2$

which is equal to...

$8 \frac{m}{s^{2}}$ $8m/s^2$ {in SI units}

If an object is moving at 3ms3 m/s and accelerates to 19ms19 m/s over 2 seconds, what was the object's rate of acceleration?