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If an object is moving at $15 m/s$ and accelerates to $19 m/s$ over 4 seconds, what was the object's rate of acceleration?

1 Answer

May 19, 2016

$a=4/4=1" " m/s^2$

Explanation:

$v_i=15 m/s" initial velocity"$
$v_f=19 m/s" final velocity"$
$t=4 s" time"$

$"acceleration of object is determined as :" a=(Delta V)/(Delta t)$

$Delta v=v_f-v_i=19-15=4$

$Delta t=t_f-t_i=4-0=4$

$a=4/4=1" " m/s^2$

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