If an object is moving at $12 m/s$ and accelerates to $32 m/s$ over 3 seconds, what was the object's rate of acceleration?

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Answer 1 · 2015-12-11T23:45:13

The acceleration is $"7 m/s"^2"$ .

$a=(v_f-v_i)/(Delta t)$ , where $a$ is acceleration, $v_f$ is final velocity, $v_i$ is initial velocity, and $Delta t$ is the time interval.

Given
$v_i="12 m/s"$
$v_f="32 m/s"$
$Delta t="3 s"$

Solution
Substitute the given values into the equation.

$a=(32"m/s"-12"m/s")/(3"s")$

$a=(20"m/s")/(3"s")$

$a="7 m/s"^2"$ (rounded to one significant figure)

If an object is moving at 12 m/s12 m/s and accelerates to 32 m/s32 m/s over 3 seconds, what was the object's rate of acceleration?