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If an object is moving at $0 m/s$ and accelerates to $90 m/s$ over 8 seconds, what was the object's rate of acceleration?

1 Answer

May 23, 2017

The rate of acceleration is $=11.25ms^-2$

Explanation:

We apply the equation of motion

$v=u+at$

The initial velocity is $u=0ms^-1$

The final velocity is $v=90ms^-1$

The time is $t=8s$

The acceleration is

$a=(v-u)/t=(90-0)/8=90/8=11.25ms^-2$

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