If an object is moving at 0 ms^-1 and accelerates to 60 ms^-1 over 24/5 seconds, what was the object's rate of acceleration?

1 Answer
David G.
Jan 15, 2016

Using the formula v = u + at, the acceleration is 12.5 ms^-2.

Explanation:

The useful formula is v = u + at, where v is the final velocity (ms^-1), u is the initial velocity (ms^-1), a is the acceleration (ms^-2) and t is the time (s).

Rearranging, a=(v-u)/t = (60-0)/(24/5) = 12.5 ms^-2

{whisper}Not sure what this US obsession with fractions is all about! I guess the answer could be expressed as 25/2 ms^-2, but why ?{/whisper}

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