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How would you write an equation of the cosine function with amplitude 2 and period 6pi?

1 Answer

Jul 9, 2016

$2 cos (\frac{x}{3})$ $2cos(x/3)$

Explanation:

The equation of the cosine function will be of the form

y = acosbx

where amplitude = |a| and period $= \frac{2 π}{b}$ $=(2pi)/b$

here |a| = |2| = 2 and $b = \frac{2 π}{6 π} = \frac{1}{3}$ $b=(2pi)/(6pi)=1/3$

Thus equation is $y = 2 cos (\frac{1}{3} x)$ $y=2cos(1/3 x)$

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