How do you write the standard equation of the circle the given center that passes with through the given point: center (0, 0); point (3, 4)?

1 Answer
Jim G.
Jul 29, 2018

x^2+y^2=25

Explanation:

"the equation of a circle in standard form is"

•color(white)(x)(x-a)^2+(y-b)^2=r^2

"where "(a,b)" are the coordinates of the centre and r is"
"the radius"

"here "(a,b)=(0,0)

(x-0)^2+(y-0)^2=r^2

x^2+y^2=r^2

"the radius is the distance from the centre to the given "
"point the circle passes through"

r=sqrt(3^2+4^2)=sqrt25=5

x^2+y^2=25larrcolor(red)"equation in standard form"

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