How do you write the equation of a sine function given Amplitude =5, Period = 2(3.14), and Phase shift = 3.14/3?

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Answer 1 · 2015-05-15T16:00:50

Consider the "template":
#y=#Amplitude#*sin((2pi)/(period)x+#Phase shift#)#
or, in your case:
#y=5sin((2pi)/(2pi)x+pi/3)=5sin(x+pi/3)#