How do you write the equation of a line in point slope form into slope intercept form given #y - 1/2 = x + 1/2#?

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Answer 1 · 2015-05-29T00:23:54

Point-slope form for a linear equation is
#(y-haty) = m(x-hatx)# for a line with slope #m# through the point #(hatx,haty)#

#y-1/2 = x+1/2#
can easily be converted into this form
#(y-1/2) = (1)(x-(-1/2))#
for a line with a slope of #1# through the point #(-1/2,+1/2)#