How do you write the equation of a line that passes through (1,1) and has slope 1/4?

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Answer 1 · 2015-04-01T12:26:25

y-1= $1/4$ (x-1)

Answer 2 · 2015-04-07T08:18:45

$(y-k)=m*(x-h)$
$m$ is the Slope of the Line

$(h,k)$ are the co-ordinates of any point on that Line.

Here, we have been given the coordinates $(h,k)$ of 1 point on that line as $(1,1)$
And the Slope $m$ is given as $1/4$

Substituting the values of h, k and m in the Point-Slope form, we get

$(y-1)=(1/4)*(x-1)$
The above will be the Equation of the Line in Point-Slope form.

Multiplying both sides with 4, we get:

$4*(y-1)=x-1$

$4y-4=x-1$

$4y=x-1+4$

$4y=x+3$

We get the equation of the line as :
$y=(1/4)*x+3/4$

The graph will look like this:

graph{y=(1/4)*x+3/4 [-10, 10, -5, 5]}