How do you write an equation of a line in slope intercept form if the line has a slope of #-2/3# and contains the point #(2,-2)#?

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Answer 1 · 2018-04-16T04:45:23

#2x + 3y + 2 = 0#

#Slope = m = -2/3, (x_1, y_1) = (2, -2)#

#![https://www.tutorpace.com/algebra/linear-equations-online-tutoring]( useruploads.socratic.org )

#"Point - Slope Form " (y - y_1) = m * (x - x_1)#

#y + 2 = -(2/3) * ( x - 2)#

#3y + 6 = -2x + 4#

#2x + 3y + 2 = 0#