How do you write the equation for a circle with points (2, 5) (6, -1) as ends of a diameter?

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How do you write the general form given a circle that passes through the given points. P(-2, 0),...
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Answer 1 · 2018-04-03T19:18:58

#(x-4)^2#+#(y-2)^2#=4

The midpoint of (2,5) and (6,-1) would be the centre of the circle.

[#(6+2)/2#,#(5+-1)/2#] #=># [4,2]

#(x-4)^2#+#(y-2)^2#=#2^2#