How do you write the complex number in standard form #3/2(cos300+isin300)#?
1 Answer
Aug 15, 2017
Explanation:
I'll assume the trigonometric arguments are in degrees.
We're asked to find the standard form of
#3/2(cos[300^"o"] + isin[300^"o"])#
Well,
And
So we have
#3/2(1/2 - (isqrt3)/2) = color(blue)(ulbar(|stackrel(" ")(" "3/4 - (3sqrt3)/4i" ")|)#