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How do you write polar coordinates of #(3, -3)#?

1 Answer

Jan 10, 2016

The coordinate (3,-3) is in Quadrant IV ....

Explanation:

#r=sqrt(x^2+y^2)=sqrt(3^2+(-3)^2)=3sqrt2#

Now, the reference angle in Quadrant IV is ...

reference angle #=tan^1(3/3)=45^0#

#theta=270^o + 45^o=315^o#

polar coordinate #(r,theta)=(3sqrt2, 315^o)=(3sqrt2,(7pi)/4)#

hope that helped

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