How do you write polar coordinates of $(3, -3)$ ?

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Answer 1 · 2016-01-10T18:31:25

The coordinate (3,-3) is in Quadrant IV ....

$r=sqrt(x^2+y^2)=sqrt(3^2+(-3)^2)=3sqrt2$

Now, the reference angle in Quadrant IV is ...

reference angle $=tan^1(3/3)=45^0$

$theta=270^o + 45^o=315^o$

polar coordinate $(r,theta)=(3sqrt2, 315^o)=(3sqrt2,(7pi)/4)$

hope that helped

How do you write polar coordinates of (3, -3)(3, -3)?