How do you write an equation of a line with points (-7,-3), (-3,5)?

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Answer 1 · 2017-04-15T21:18:45

#y = 2x + 11 #

Put the equation in the # y = mx + b # form .

Find the slope of the equation by solving for

#m = ( y_1- y_2)/(x_1- x_2) #

Substituting the points for y and x gives

#m = (-3 -5)/( -7 - (-3) #= # -8/-4 = 2#

The slope: #m = 2 #

Putting #2# in for #m# and the values for #(x, y)# gives

# 5 = 2(-3) + b# This results

# 5 = -6 + b add six to both sides

# 5+ 6 = -6 +6 + b#

#11 = b#

So the equation is # y = 2x + 11#