How do you write an equation of a circle with its center in quadrant I, radius of 5 units and tangents at x=2 and y=3?

Question

How do you write the general form given a circle that passes through the given points. P(-2, 0),...
What is the equation of the circle with a center at $(7 ,1 )$ and a radius of $2$ ?
What is the equation of the circle with a center at $(3 ,1 )$ and a radius of $2$ ?
What is the equation of the circle with a center at $(3 ,1 )$ and a radius of $1$ ?
What is the equation of the circle with a center at $(3 ,5 )$ and a radius of $1$ ?
What is the equation of the circle with a center at $(3 ,5 )$ and a radius of $6$ ?
What is the equation of the circle with a center at $(2 ,5 )$ and a radius of $6$ ?
What is the equation of the circle with a center at $(2 ,2 )$ and a radius of $4$ ?
What is the equation of the circle with a center at $(2 ,2 )$ and a radius of $3$ ?
What is the equation of the circle with a center at $(2 ,1 )$ and a radius of $3$ ?

2076 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-05T09:24:17

$x^2+y^2-14x-16y+88=0$

The lines $x=2$ and $y=3$ intersect at $(2,3)$

and divide Quadrant I, in four parts. As radius is $5$ , we can have circle only in right hand top portion

and hence center could be only at $(7,8)$ and equation of circle is

$(x-7)^2+(y-8)^2=25$

or $x^2-14x+49+y^2-16y+64=25$

or $x^2+y^2-14x-16y+88=0$
graph{(x-2)(y-3)(x^2+y^2-14x-16y+88)=0 [-15.33, 24.67, -2.68, 17.32]}