How do you write an equation of a circle with diameter that has endpoints (-7,-2), and (-15,6)?

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How do you write the general form given a circle that passes through the given points. P(-2, 0),...
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Answer 1 · 2017-08-02T12:28:00

The equation of the circle is #(x+11)^2+(y-2)^2=32#

The points on the diameter are #A=(-7,-2)# and #B=(-15,6)#

The midpoint of #AB# is the center of the circle

#O=(((-7)+(-15))/2, ((-2)+(6))/2)=(-11,2)#

The radius of the circle is

#r^2=((-7+11)^2+(-2-2)^2)=(4^2+4^2)=32#

The equation of the circle is

#(x+11)^2+(y-2)^2=r^2=32#

graph{(x+11)^2+(y-2)^2=32 [-23.04, 2.27, -3.43, 9.24]}