How do you write an equation of a circle with center at (-8,8), d=16?

1 Answer
Dec 22, 2016

(x+8)^2+(y-8)^2=64

Explanation:

The standard form of the equation of a circle is.

color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y=b)^2=r^2)color(white)(2/2)|)))
where (a ,b) are the coordinates of the centre and r, the radius.

"here " a=-8,b=8" and " r=16/2=8

substituting these values into the equation.

(x-(-8))^2+(y-8)^2=8^2

rArr(x+8)^2+(y-8)^2=64" is the equation of the circle"