How do you write an equation of a circle with center at (5,10), r=7?

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Answer 1 · 2017-03-17T03:29:20

$(x-5)^2 + (y-10)^2 = 49$

Standard equation of a circle: $(x-h)^2 + (y-k)^2 = r^2$ , where $"center": (h, k), r = "radius"$

$r = 7$ , so $r^2 = 7^2 = 49$
$h = 5, k = 10$

So: $(x-5)^2 + (y-10)^2 = 49$