How do you write an equation of a circle with center at (0,5), d=20?

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How do you write an equation of a circle with center at (0,5), d=20?

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Answer 1 · 2018-04-18T12:40:29

Assuming $d$ is the radius, the answer is $x^2 + (y-5)^2 = 20^2$

Explanation:

I'm not sure what $d$ is here, let's assume it's the radius.

The general equation of a circle with center $(a,b)$ and radius $r$ is

$(x - a)^2 + (y-b)^2 = r^2$

So in our case that's

$(x - 0)^2 + (y - 5)^2 = 20^2$

$x^2 + (y-5)^2 = 400$

Answer 2 · 2018-04-18T13:24:52

$x^2+(y-5)^2=100$

Explanation:

$"the standard form of the equation of a circle is"$

$color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))$

$"where "(a,b)" are the coordinates of the centre and r"$
$"is the radius"$

$"here "(a,b)=(0,5)" and r=d/2=20/2=10$

$rArr(x-0)^2+(y-5)^2=10^2$

$rArrx^2+(y-5)^2=100larrcolor(red)"equation of circle"$

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How do you write an equation of a circle with center at (0,5), d=20?

2 Answers

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