How do you write an equation of a circle with center at (0,0), d=12?

Question

How do you write the general form given a circle that passes through the given points. P(-2, 0),...
What is the equation of the circle with a center at #(7 ,1 )# and a radius of #2 #?
What is the equation of the circle with a center at #(3 ,1 )# and a radius of #2 #?
What is the equation of the circle with a center at #(3 ,1 )# and a radius of #1 #?
What is the equation of the circle with a center at #(3 ,5 )# and a radius of #1 #?
What is the equation of the circle with a center at #(3 ,5 )# and a radius of #6 #?
What is the equation of the circle with a center at #(2 ,5 )# and a radius of #6 #?
What is the equation of the circle with a center at #(2 ,2 )# and a radius of #4 #?
What is the equation of the circle with a center at #(2 ,2 )# and a radius of #3 #?
What is the equation of the circle with a center at #(2 ,1 )# and a radius of #3 #?

3039 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-13T17:49:47

The standard Cartesian form for the equation of a circle is:

#(x - h)^2 + (y - k)^2 = r^2" [1]"#

where (h,k) is the center and r is the radius.

Given: center# = (0,0) and d = 12#

Use the diameter to compute the radius:

#r = d/2#

#r = 12/2#

#r = 6#

Substitute the center and the radius into equation [1]:

#(x - 0)^2 + (y - 0)^2 = 6^2" [2]"#

Equation [2] is the answer.