How do you write an equation of a circle with center at (0,0), d=12?

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Answer 1 · 2017-01-13T17:49:47

The standard Cartesian form for the equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2" [1]"$

where (h,k) is the center and r is the radius.

Given: center $= (0,0) and d = 12$

Use the diameter to compute the radius:

$r = d/2$

$r = 12/2$

$r = 6$

Substitute the center and the radius into equation [1]:

$(x - 0)^2 + (y - 0)^2 = 6^2" [2]"$

Equation [2] is the answer.