How do you write an equation in standard form given a line that passes through (-5,-2) with slope -3?

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Answer 1 · 2015-05-27T13:52:19

Given the point #(-5,-2)# and the slope #(-3)# we can easily write the linear equation in slope-point form and then convert it to standard form.

Slope-Point Form
#(y-y_1) = m(x-x_1)# for a slope of #m# and a point #(x_1,y_1)#
becomes
#(y-(-2))= (-3)(x-(-5))#
or
#y+2 = (-3)(x+5)#

Standard Form
Standard form of a linear equation is
#Ax+By=C# with #A>=0 and AepsilonZZ#
#y+2 = (-3)(x+5)#
#rarr y+2 = -3x -15#

#rarr 3x+1y = -17#

which is in standard form