How do you write an equation in standard form for a line with y- intercept of 3/2 and slope of m = 1/2?

1 Answer
Alan P.
Jun 1, 2015

In slope-intercept form, a line with y-intercept of #3/2# and a slope of #m=1/2# would be written as
#color(white)("XXXXX")##y=1/2x+3/2#

Standard form is (normally)
#color(white)("XXXXX")##Ax+By=C# where #A>=0 and AepsilonZZ#

Converting to standard form.
Multiply everything by 2 to clear the fractions
#color(white)("XXXXX")##2y=1x+3#
Subtract #2y+3# from both sides (and flip the sides)
#color(white)("XXXXX")##1x-2y = -3#
#color(white)("XXXXX")##color(white)("XXXXX")#which is in standard form

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