How do you write #(9y^6) ^(3/2)# as a radical form?

1 Answer
EZ as pi
Aug 2, 2016

#(9y^6) ^(3/2) # can be written as #sqrt((9y^6))^3#
It simplifies to #27y^9#

Explanation:

One of the laws of indices states that #x^(p/q) = rootq(x)^p#

(The denominator or the index is the root and the numerator is the power)

#(9y^6) ^(3/2) # can be written as #sqrt((9y^6))^3#

This can be simplified:
#=(3y^3)^3#

=#27y^9#

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