How do you simplify ${(\frac{3 x}{y^{\frac{1}{3}}})}^{3}$ $((3x)/(y^(1/3)))^3$ without any fractions in the answer?

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Answer 1 · 2018-03-29T03:32:45

$27 x^{3} y^{- 1}$ $27x^3y^{-1}$

${(\frac{3 x}{y^{\frac{1}{3}}})}^{3}$ $(frac{3x}{y^{frac{1}{3}}})^3$

$\frac{{(3 x)}^{3}}{{(y^{\frac{1}{3}})}^{3}}$ $frac{(3x)^3}{(y^{frac{1}{3}})^3}$

$\frac{3^{3} x^{3}}{y}$ $frac{3^3x^3}{y}$

$\frac{27 x^{3}}{y}$ $frac{27x^3}{y}$

$27 x^{3} y^{- 1}$ $27x^3y^{-1}$

How do you simplify (3xy13)3((3x)/(y^(1/3)))^3 without any fractions in the answer?